Check if two Strings are Anagram in Python

def main():
	"""
	Prints if two strings are anagram.
	"""

	a = input("Enter string A: ")
	b = input("Enter string B: ")

	r = is_anagram(a, b)
	print(r)


def is_anagram(a: str, b: str):
	"""
	Checks if two English words are anagram.
	"""

	a_counts = frequency(a)
	b_counts = frequency(b)
	return a_counts == b_counts


def frequency(text: str):
	"""
	Counts the frequency of English letter in a string.
	"""

	# Represent the frequency of 26 English letters in an array
	counts = [0] * 26

	# Count the occurrences of each lower cased English letter
	for c in text:
		c = c.lower()
		if "a" <= c < "z":
			counts[ord(c) - ord("a")] += 1

	return counts


if __name__ == "__main__":
	main()

def main():
	"""
	Prints if two strings ignoring spaces are anagram.
	"""

	a = input("Enter string A: ")
	b = input("Enter string B: ")

	r = is_anagram(a, b)
	print(r)


def is_anagram(a: str, b: str):
	"""
	Checks if two Unicode strings are anagram.
	"""

	a_counts = frequency(a)
	b_counts = frequency(b)
	return a_counts == b_counts


def frequency(text: str):
	"""
	Counts the frequency of each character in a string ignoring spaces.
	"""

	# Represent the frequency of characters using dictionary
	counts: dict[str, int] = dict()

	# Count the occurrences of each character excluding spaces
	for c in text:
		if c.isspace():
			continue
		elif c not in counts:
			counts[c] = 1
		else:
			counts[c] += 1

	return dict(sorted(counts.items()))


if __name__ == "__main__":
	main()